Bull. Korean Math. Soc. 2017; 54(6): 2141-2147
Online first article July 26, 2017 Printed November 30, 2017
https://doi.org/10.4134/BKMS.b160783
Copyright © The Korean Mathematical Society.
Mohammad Hossein Jafari, Ali Reza Madadi
University of Tabriz, University of Tabriz
Let $G$ be a finite group and $m$ a divisor of $|G|.$ We prove that $G$ has at least $\tau(m)$ cyclic subgroups whose orders divide $m$, where $\tau(m)$ is the number of divisors of $m.$
Keywords: cyclic subgroups, Sylow subgroups, arithmetic functions
MSC numbers: 20D15, 20D20, 11A25
2015; 52(3): 717-734
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