    - Current Issue - Ahead of Print Articles - All Issues - Search - Open Access - Information for Authors - Downloads - Guideline - Regulations ㆍPaper Submission ㆍPaper Reviewing ㆍPublication and Distribution - Code of Ethics - For Authors ㆍOnlilne Submission ㆍMy Manuscript - For Reviewers - For Editors       Self-reciprocal polynomials with related maximal zeros Bull. Korean Math. Soc. 2013 Vol. 50, No. 3, 983-991 https://doi.org/10.4134/BKMS.2013.50.3.983Printed May 31, 2013 Jaegug Bae and Seon-Hong Kim Korea Maritime University, Sookmyung Women's University Abstract : For each real number $n>6$, we prove that there is a sequence $\{ p_k(n,z)\}_{k=1}^{\infty}$ of fourth degree self-reciprocal polynomials such that the zeros of $p_k(n,z)$ are all simple and real, and every $\, p_{k+1}(n,z)$ has the largest (in modulus) zero $\alpha \beta$ where $\alpha$ and $\beta$ are the first and the second largest (in modulus) zeros of $p_{k}(n,z)$, respectively. One such sequence is given by $p_{k}(n,z)$ so that $$p_{k}(n,z)= z^4 -q_{k-1}(n)\,z^3+(q_k(n)+2)\,z^2-q_{k-1}(n)\,z+1,$$ where $q_0(n)=1$ and other $q_k(n)$'s are polynomials in $n$ defined by the severely nonlinear recurrence \begin{align*} 4q_{2m-1}(n)&=q_{2m-2}^{2}(n)-(4n+1)\prod_{j=0}^{m-2}q_{2j}^{2}(n),\\ 4q_{2m}(n)&=q_{2m-1}^{2}(n)-(n-2)(n-6)\prod_{j=0}^{m-2}q_{2j+1}^{2}(n) \end{align*} for $m\ge1$, with the usual empty product conventions, i.e., $\prod_{j=0}^{-1}b_j=1$. Keywords : self-reciprocal polynomials, polynomials, sequences MSC numbers : Primary 11B83; Secondary 30C15 Downloads: Full-text PDF

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